http://asciimath.org/
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When {`a != 0`}, there are two solutions to {`ax^2 + bx + c = 0`} and they are
{`x_(1,2) = (-b +- sqrt(b^2-4ac))/(2a) .`}
sum: {`sum_(i=1)^n i^3=((n(n+1))/2)^2`}